Question

racing car has uniform acceleration of 4 metre per second square what distance will it cover in 20 seconds after the start​

Answer 1

Answer:-

Here initial velocity=u

final velocity=v

acceleration=a

time=t

u=0

a=4

t=20

using 2nd equation of motion

that is S = ut + ½ at ²

½ x 4 (20)²

2 x 400

= 800 metres.

hence the distance covered is 800metre.

hope it helps...

Answer 2

Answer:

s = 800m

Explanation:

a = 4 m/s²

t = 20 s

u = 0 m/s

so, s( distance ) = ut + ½at²

= 0×20 + ½×4×20×20

= 0 + 2×400

= 800m

therefore, distance covered = 800m