racing car moving with constant acceleration covers two successive kilometres in 30 seconds and 20 seconds respectively find the acceleration of the car and initial speed
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Let u be the initial velocity and a be the acceleration.
1000 = u(30) + 0.5a(30)(30)= 30u + 450a
Velocity after covering 1 km is u + 30a
1000 = (u + 30a)(20) + 0.5a(20)(20)= 20u + 800a
Solving we get u = 35a
Therefore, a = (2/3)
1000 = u(30) + 0.5a(30)(30)= 30u + 450a
Velocity after covering 1 km is u + 30a
1000 = (u + 30a)(20) + 0.5a(20)(20)= 20u + 800a
Solving we get u = 35a
Therefore, a = (2/3)
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