racing car starting from rest has uniform acceleration of 0.2 metre per second square for 5 minutes calculate the average speed of the train also find out the distance covered
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Given,
u (initial speed) = 0 m/s
a (acceleration) = 0.2 m/s
t (time) = 5 minutes
Now, we will convert the time into seconds for making the units comparable. 5* 60 = 300 seconds
Now final speed of the vehicle = v = u + at = 0 + 0.2* 300 = 60 m/s
Now, average speed = 0 + 60/ 2 = 30 m/s Ans.
Distance covered = 300* 30 = 9000 m Ans.
u (initial speed) = 0 m/s
a (acceleration) = 0.2 m/s
t (time) = 5 minutes
Now, we will convert the time into seconds for making the units comparable. 5* 60 = 300 seconds
Now final speed of the vehicle = v = u + at = 0 + 0.2* 300 = 60 m/s
Now, average speed = 0 + 60/ 2 = 30 m/s Ans.
Distance covered = 300* 30 = 9000 m Ans.
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