Question

Radha bought 4 3/4 of kg sugar
and 5 1/3 potatoes. What is the total weight of items she purchased?​

Answer 1

Answer:

$\boxed{\bf \: Total\:weight \: of \: items \: she \: purchaed = 10\dfrac{1}{12} \: kg \: }$

Step-by-step explanation:

Given that,

$\sf \: Quantity\:of\:sugar\:purchased\:by\:Radha$

$\sf \: = \: 4\dfrac{3}{4} \: kg$

$\sf \: = \: \dfrac{4 \times 4 + 3}{4} \: kg$

$\sf \: = \: \dfrac{16 + 3}{4} \: kg$

$\sf \: = \: \dfrac{19}{4} \: kg$

Further given that,

$\sf \: Quantity\:of\:potatoes\:purchased\:by\:Radha$

$\sf \: = \: 5\dfrac{1}{3} \: kg$

$\sf \: = \: \dfrac{5 \times 3 + 1}{3} \: kg$

$\sf \: = \: \dfrac{15 + 1}{3} \: kg$

$\sf \: = \: \dfrac{16}{3} \: kg$

Now,

$\sf \: Total\:weight \: of \: items \: she \: purchaed$

$\sf \: = \: Quantity\:of\:sugar + Quantity\:of\:potatoes$

$\sf \: = \: \dfrac{19}{4} + \dfrac{16}{3}$

$\sf \: = \: \dfrac{19 \times 3}{4 \times 3} + \dfrac{16 \times 4}{3 \times 4}$

$\sf \: = \: \dfrac{57}{12} + \dfrac{64}{12}$

$\sf \: = \: \dfrac{57 + 64}{12}$

$\sf \: = \: \dfrac{121}{12}$

$\sf \: = \: 10\dfrac{1}{12} \: kg$

Hence,

$\implies \boxed{\bf \: Total\:weight \: of \: items \: she \: purchaed = 10\dfrac{1}{12} \: kg \: }$