Question

Radha is twice as old as Meera. Five years ago her age was three times Meera’s age. Find their present ages.

Answer 1

Answer:

Radha's age=20, Meera's age=10

Step-by-step explanation:

Let meera's present age be x

therefore, present ages=

radha=2x

meera=x

therefore, we can derive the equation 2x-5=3(x-5)

so,x=10

therefore, radha's age=2x=2*10=20& meera's age=x=10

Answer 2

Answer:

Let the present age of meera be x years and present age of merra's mother be y years.

It is given in the question that meera's mother is four times as old as Meera :]

➴ y = 4x........(Equation [1])

After 5 years,

Age of meera = (x + 5) years.

Age of merra's mother = (y + 5) years.

➴ (y + 5) = 3(x + 5)............(Equation [2])

Now, Putting equation (1) in equation (2) we get :

➳ 4x + 5 = 3x + 15

➳ 4x - 3x = 15 - 5

➳ x = 10 years

Now, Putting the value of x = 10 in equation (1) we get :

➳ y = 4x

➳ y = 4(10)

➳ y = 40 years

Therefore,

Present Age of meera = 10 years.

Present Age of merra's mother= 40 years.