Question

Radha is twice as old as Mohini. After 3 years, Radha's age will be 3/2 times the age of Mohini. Find their present ages.

Answer 1

Required Answer :

Present age of Radha = 6 years

Present age of Mohini = 3 years

Given :

• Radha is twice as old as Mohini

• Radha's age will be 3/2 times the age of Mohin after 3 years.

To find :

• The present age of Radha and Mohini

Solution :

Let,

→ The present age of Mohini = x years

→ The present age of Radha = 2(Age of Mohini)

→ The present age of Radha = 2x years

Their ages after 3 years :-

→ Age of Mohini = x + 3 years

→ Age of Radha = 2x + 3 years

According to the question,

→ Age of Radha = 3/2 (Age of Mohini)

→ 2x + 3 = 3/2 (x + 3)

→ 2(2x + 3) = 3(x + 3)

→ 4x + 6 = 3x + 9

→ 4x - 3x = 9 - 6

→ x = 3

→ The value of x = 3

Substitute the value of 'x' in the present ages of Radha and Mohini :-

Present age of Mohini :-

→ Present age of Mohini = x

→ Present age of Mohini = 3 years

→ Present age of Radha = 2(Age of Mohini)

→ Present age of Radha = 2(3)

→ Present age of Radha = 6 years

Answer 2

❍Given:

• Radha is twice as old as Mohini.

• After 3 years, Radha's age will be 3/2 times the age of Mohini

❍To Find:

• Present Ages.

❍Solution:

• Let present age of mohini be x years
• Present age of radha = 2x

After three years:

• Mohini's age = x + 3 years
• Radha's age = 2x + 3 years

According to Question:

Age of radha = 3/2 (age ofmohini)

➠ 2x + 3 = 3/2 (x + 3)

➠ 2 (2x + 3) = 3 (x + 3)

➠ 4x - 3x = 9 - 6

➠ x = 3

Now, Present ages:

• Present Age of mohini = x = 3 years
• Present age of radha = 2x = 6 years