Question

Radha made a picture of an aeroplane with coloured paper as shown in Fig 12.15
Find the total area of the paper
used.

​

Answer 1

Step-by-step explanation:

For surface I:

It is an isosceles triangle whose sides are a = 5 cm, b = 5 cm, c = 1 cm

NCERT Solutions for Class 9 Maths Chapter 12 Heron’s Formula Ex 12.2 A3

= (0.75 x 3.3) cm2

= 2.475 cm2 (approx.)

For surface II:

It is a rectangle with length 6.5 cm and breadth 1 cm.

∴ Area of surface II = Length x Breadth

= (6.5 x 1) cm2 = 6.5 cm2

NCERT Solutions for Class 9 Maths Chapter 12 Heron’s Formula Ex 12.2 A3a

For surface III:

It is a trapezium whose parallel sides are 1 cm and 2 cm as shown in the figure given below:

NCERT Solutions for Class 9 Maths Chapter 12 Heron’s Formula Ex 12.2 A3b

For surface IV and V:

Surface V is a right-angled triangle with base 6cm arid height 1.5 cm.

Also, area of surface IV = area of surface V

= \frac { 1 }{ 2 } x base x height

= (\frac { 1 }{ 2 } x 6 x 15) cm2 = 4.5 cm2

Thus, the total area of the paper used = (area of surface I) + (area of surface II) + (area of surface III) + (area of surface IV) + (area of surface V) = [2.475 + 6.5 + 1.3 + 4.5 + 4.5] cm2

= 19.275 cm2

= 19.3 cm2 (approx.)

solution is too long but here is your answer.

Answer 2

Answer:

:-)

Step-by-step explanation:

agar thumhe mil jaye iska pura explanation tohh mujhe bhi bhej dena mujhe bhi yahi karna h :-) (-: