Radha made a picture of an aeroplane with coloured paper as shown in Fig 12.15. Find the total area of the paper used.
Answers
for surface 1
s=a+b+c/2
=5+5+1/2
=11/2cm
area of surface 1=√S (S-a)(S-b)(S-c)
=√11/2(11/2-5)(11/2-5)(11/2-1)
=√11/2×1/2×1/2×9/2
=3/4√11cm^
=(0.75×33)
=2.475cm^(approx)
for surface 2
it is a rectangle
area of surface 2: L×B
6.5×1
6.5cm^
it's height is given
=1/2[(sum of parallel sides)×h]
area of surface 3
=1/2×[(2+1)×√3/2]
3√3/4
3.1.732/4
1.3cm^(approx)
for surface 3
it's height is given by
h=√(1)^-(1/2)^
=√1-1/4
=√3/4
=√3/2cm
area of trapezium
=1/2[(sum of the parallel sides)×h]
area of surface 3
=1/2×[(2+1)×√3/2]
=3√3/4
=3×1.732/4
=1.3cm^(approx)
for surface 4 and 5
area of surface 4 = area of surface 5
1/2×b×h
1/2×6×15
4.5cm^
total are of paper used =(ar of surface 1)+(ar of surface 2)+(ar of surface 3)+(ar of surface 4)+(ar of surface 5)
=(2.475+6.5+1.3+4.5+4.5)
= 19.275
= 19.3cm^(approx)