Question

radha made a plane from a page.
then find out the area of page

i give you 100 points

Answer 1

1..
area of ∆ABC=√(s(s-a)(s-b)(s-c))
here a=1,b=5,c=5
s=(a+b+c)/2
=(5+5+1)/2
=11/2
=√((11/2(11/2-1)(11/2-5)(11/2-5))
=√((11/2)(9/2)(1/2)(1/2))
=√(11×9×(1/2)⁴)
=3×(1/2)²√11
=3/4(3.38)
=2.48cm²
2...
rectangle with length=6.5 cm
breadth=1 cm
=6.5×1=6.5cm²
3...
after drawing PM perpendicular to SR and QN perpendicular to SR..
area of 3=area of i) +area of ii)+area of iii)
i) and iii) are right triangles
area of i)+area of ii)=2area i) ......by symmetry
=1/2×2×0.5×1=0.5 cm²
ii) is a rectangle
area of ii)=l× b=1×1=1cm²
area of 3...=area of i)+area of ii)+area of iii)
=0.5+1
=1.5
4....and 5...
area of ∆=1/2×6×1.5=4.5
and then....
area of plane=area1+area2+area3+area4+area5
=2.48+6.5+1.5+4.5+4.5
=17.0+2.48
=19.48
19.4(approx.)

Answer 2

Answer:

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Step-by-step explanation: