Math, asked by arshchadha001, 24 days ago

Radha sold two fridge for *x each. On selling
one fridge, she gained 20% and on selling the
other, she beared a loss of 20%. If her overall
gain/loss percentage in whole transaction is y%
and cost price of 1 fridge is 5000 such that x>
5000, then the sum of y, numerical value of cost
y
price of other fridge and selling price of 1 fridge
is

Answers

Answered by namdeoshikhu777
1

Answer:

Sp of buffalo1 = Rs 20,000

Gain =5%

So, Cost price of buffalo1 =

105

100

×20,000= Rs. 19047.62

SP of buffalo2 = Rs 20,000

Loss =10%

Cost price of buffalo2 =

90

100

×20,000= Rs 22,222.22

Total Cost price = Rs 41269.84

Total selling price = Rs 40,000

Loss = Rs 1269.84

Answered by seemon29
0

Answer:

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