Question

Radha takes some flowers in a basket and visits three temples one-by-one. At each temple,
she offers one half of the flowers from the basket. If she is left with 3 flowers at the end, then
find the number of flowers she had in the beginning.​

Answer 1

Answer :-

24

Explanation :-

Given :

Radhika takes some flower and visited three temples one-by-one, she offer one half of the flowers at each temples and left with 3 flower at the end.

To Find :

Number of the flowers she had in the beginning

Solution :

Let the total number of flower she had in the beginning every “x”

Number of flowers she gave in the first temple = total number of flower × half

$\rm{} \implies x\times \dfrac{1}{2}$

$\rm{} \implies \dfrac{x}{2}$

Number of flowers she gave in the second temple = number of flower left after offering it in first temple × half

$\rm{} \implies \dfrac{x}{2}\times \dfrac{1}{2}$

$\rm{} \implies \dfrac{x}{4}$

Number of flowers she gave in the second temple = number of flower left after offering it in second temple × half

$\rm{} \implies \dfrac{x}{4}\times \dfrac{1}{2}$

$\rm{}\implies \dfrac{x}{8}$

According to the question,

Total flower she had in the beginning - Total number of flower she offered in three temples = Remaining flowers

$\rm{}\implies x-\bigg(\dfrac{x}{2}+ \dfrac{x}{4}+ \dfrac{x}{8}\bigg)=3$

$\rmf{}\implies x-\bigg(\dfrac{4\times x+ 2\times x+x}{8}\bigg)=3$

$\rm{}\implies x-\bigg(\dfrac{4x+ 2x+x}{8}\bigg)=3$

$\rm{}\implies x-\dfrac{7x}{8}=3$

$\rm{}\implies \dfrac{x\times 8+7x}{8}=3$

$\rm{}\implies \dfrac{8x-7x}{8}=3$

$\rm{}\implies \dfrac{x}{8}=3$

$\rm{}\implies x=3\times 8$

$\sf{} \therefore x=24$

Therefore, she had 24 flowers in the beginning