Radhika and Niharika borrowed rs 21000 and rs 15000 repectively at same rate of simple intrest for 4 years . If Radhika paid rs 1440 more intrest than Niharika, find the rate of intrest per annum.
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Step-by-step explanation:
Radhika borrowed =Rs.12000
i. Principal =Rs.4000,
Time =3years
R=18%p.a.
Now,
Interest=
100
4000×18×3
=Rs.2160
ii. Principal =12000−8000=Rs.4000,
Time =3years
R=15%p.a.
Now,
Interest=
100
8000×15×3
=Rs.3600
Total interest =2160+3600=Rs.5760
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