Question

. Radhika bought a car for Rs 2,50,000. Its price decreased by 10% every year. What will be its price after 2 years?

Answer 1

Answer:

Radhika bought a car for Rs. 250000.

Cost price of the car Rs. 250000

It's price decreased next year for 10%

so price becomes

\begin{gathered}250000 - \frac{10}{100} \times 250000 \\ \\ = rs.225000\end{gathered}

250000−

100

10

×250000

=rs.225000

Future next year, it's price decreased by 12%, then price will be,

\begin{gathered}225000 - 225000 \times \frac{12}{100} \\ \\ = rs.198000\end{gathered}

225000−225000×

100

12

=rs.198000

In two years,

overall decease percent

\begin{gathered}= \frac{250000 - 19800}{250000} \times 100 \\ \\ = 20.8\%\end{gathered}

=

250000

250000−19800

×100

=20.8%

Hence, option (c) 20.8% is the correct answer.

Answer 2

Answer:

Cost of car after 2 years = ₹ 2,02,500

Step-by-step explanation:

The cost of Car = ₹ 2,50,000/-

The decrease in cost of car for first year

= 10/100 × 2,50,000

= ₹25,000

So the cost of car after 1 year = 2,50,000 - 25,000

= ₹2,25,000

The decrease in cost of car for second year

= 10/100 × 2,25,000

= ₹22,500

So the cost of car after 2 years = 2,25,000 - 22,500

= ₹2,02,500