Math, asked by vinodtomar88, 1 year ago

Radhika finishes2/7 of her homework in the first week and 3/5 in the second week. What part of the homework remains to be finished in the third and fourth weeks of her holidays?

Answers

Answered by fiercespartan
26
Hey!!

Let us take the total home work as ' x '

Finished 2 ÷ 7 on first week

Finished 3 ÷ 5 on second week

If we add them

( 2 ÷ 7 ) + ( 3 ÷ 5 )

LCM = 35

10 + 21 ÷ 35

31 ÷ 35

Now, home work left =

1 - ( 31 ÷ 35 )

LCM = 35

35 - 31 ÷ 35

4 ÷ 35 home work is left

Hope my answer helps!

#PeaceOut

#FIERCE

Leukonov: you made a typo, my friend.. 10 +21=31. its not 32.
vinodtomar88: I know my friend Sorry!!! for that !!!
vinodtomar88: Thanks for that solution!!!!!!!!✌️✌️✌️
Leukonov: Anytime... Its my pleasure
Answered by Leukonov
16
Given:
Radhikha finished...
2/7 part of Homework in 1st week
3/5 part in 2nd week

Let the remaining Homework be 'x'

Then (2/7 + 3/5) + x = 1
→31/35 +x =1
→x = 1- (31/35)
→x=4/35

so In all...
if we divide her homework into 35 parts
she finished::
10 parts in week 1
21 parts in week 2
now Only 4 parts remain to be completed within week 3 and week 4

vinodtomar88: Thanks!!!
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