Question

Radhika got first price in sports championship of her school so her parents bought cake. That day she eats ½ of the cake. On the next day, she eats 1/3 of the remaining cake, on the third day she eats ¼ and fourth 1/5, fifth day 1/6, on the sixth day she eats 1/7th of what is remaining and so on….. If after 4th day cake gets spoil, how much of cake is still available? * 1 point 0.25 1234/2345 1/5 0.12345​

Answer 1

Solution :-

Let us assume that, her parents bought (2 * 3 * 4 * 5 * 6 * 7) 5040 gm of cake for radhika .

So,

→ First day she ate = (1/2) * 5040 = 2520 gm of cake .

→ Left cake after 1st day = 2520 gm .

Now,

→ 2nd day she ate = (1/3) * 2520 = 840 gm of cake .

→ Left cake after 2nd day = 2520 - 840 = 1680 gm .

and,

→ Third day she ate = (1/4) * 1680 = 420 gm of cake

→ Left cake after 3rd day = 1680 - 420 = 1260 gm .

again,

→ Fourth day she ate = (1/5) * 1260 = 252 gm of cake

→ Left cake after 4th day = 1260 - 252 = 1008 gm .

Now, When cake spoil after 4th day .

→ Cake still available = 1008/5040 = 1/5 (c) (Ans.)

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Answer 2

Solution :

Let us assume that, her parents bought (2

3 * 4 * 5 *6* 7) 5040 gm of cake for radhika.

So,

→ First day she ate = (1/2)* 5040 = 2520 gm of cake.

→ Left cake after 1st day = 2520 gm.

Now,

→ 2nd day she ate = (1/3)* 2520 = 840 gm of cake.

→ Left cake after 2nd day = 2520 - 840 = 1680 gm .

and,

→ Third day she ate = (1/4) * 1680 = 420 gm of cake

→ Left cake after 3rd day = 1680-420= 1260 gm .

again,

→ Fourth day she ate = (1/5) * 1260 = 252 gm of cake

→ Left cake after 4th day = 1260-252 = 1008 gm.

Now, When cake spoil after 4th day.

→ Cake still available = 1008/5040 = 1/5 (c) (Ans.)