Question

Radhika is 5 years younger than sonika sum of their ages after 6 years is 47 years age of Radhika ​

Answer 1

Answer:

let the age of sonika = x

let the age of radhika = 5 years younger than x =

x - 5

after 6 years

age of sonika = x + 6

age of radhika = x - 5 + 6 = x + 1

sum of their ages after 6 years = 47

x + 6 + x + 1 = 47

2x + 7 = 47

2x = 47 - 7

2x = 40

x = 40/2

x = 20

therefore age of sonika = 20

age of radhika = 15

I think this is the answer...........I hope it helps you

Answer 2

Answer:

Let Rohit's age be x years.

Since, Ritu is 5 years younger than her brother Rohit, her age =x−5

Given, father is 25 years older than Ritu => Father's age =x−5+25=x+20

Four years ago, Rohit's age =x−4, Ritu's age =x−9, Father's age =x+16

Given, four years ago, the fathers age was twice the sum of the ages of Rohit and Ritu

=>x+16=2(x−4+x−9)

=>x+16=4x−26

=>3x=42

x=14

Hence, Rohit's age =14 years

Ritu's age =x−5=9 years

Father's age =x+20=34 years

Just change the names