Radhika is 5 years younger than sonika sum of their ages after 6 years is 47 years age of Radhika
Answers
Answer:
let the age of sonika = x
let the age of radhika = 5 years younger than x =
x - 5
after 6 years
age of sonika = x + 6
age of radhika = x - 5 + 6 = x + 1
sum of their ages after 6 years = 47
x + 6 + x + 1 = 47
2x + 7 = 47
2x = 47 - 7
2x = 40
x = 40/2
x = 20
therefore age of sonika = 20
age of radhika = 15
I think this is the answer...........I hope it helps you
Answer:
Let Rohit's age be x years.
Since, Ritu is 5 years younger than her brother Rohit, her age =x−5
Given, father is 25 years older than Ritu => Father's age =x−5+25=x+20
Four years ago, Rohit's age =x−4, Ritu's age =x−9, Father's age =x+16
Given, four years ago, the fathers age was twice the sum of the ages of Rohit and Ritu
=>x+16=2(x−4+x−9)
=>x+16=4x−26
=>3x=42
x=14
Hence, Rohit's age =14 years
Ritu's age =x−5=9 years
Father's age =x+20=34 years
Just change the names