Question

Radhika is heating a liquid. The temperature of liquid before heating was recorded as 25°C and after heating was recorded as 300K. Find the difference in temperature.

Please tell me with explaination.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

Given :      α=0.00125/  

o

C

Using          R  

T

​

=R  

273

​

(1+α(T−273))          

For   T=300,        R  

300

​

=1Ω

∴       R  

300

​

=R  

273

​

(1+α(300−273))  

OR         1=R  

273

​

(1+0.00125(300−273))              ⟹R  

273

​

=0.967Ω      

Let at temperature be T when   R  

T

​

=2Ω  

∴         R  

T

​

=R  

273

​

(1+α(T−273))  

OR      2=0.967(1+0.00125(T−273))  

OR      T−273=854.6

⟹    T=273+854.6=1127.6K

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