Question

Radhika is playing with a six faced dice having
the possible outcomes as 2, 5, 9, 11, 13 and 15.
She throws dice two times. The probability of
getting atleast one outcome as prime number is
р
q (where p and q are coprime). The value of
2pq is​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Given :- Radhika is playing with a six faced dice having the possible outcomes 2,5,9,11,13 and 15. she throws dice two times. The probability of getting atleast one outcome as prime number is p/q (where p and q are coprime). The value of √2pq is ?

Solution :-

In a throw of pair of dice, total no of possible outcomes are = 6 * 6 = 36.

which are :-

• (2,2) (2,5) (2,9) (2,11) (2,13) (2,15)
• (5,2) (5,5) (5,9) (5,11) (5,13) (5,15)
• (9,2) (9,5) (9,9) (9,11) (9,13) (9,15)
• (11,2) (11,5) (11,9) (11,11) (11,13) (11,15)
• (13,2) (13,5) (13,9) (13,11) (13,13) (13,15)
• (15,2) (15,5) (15,9) (15,11) (15,13) (15,15)

So,

• Total Number of favorable outcomes as atleast one outcome as prime number are = 32 .

Therefore,

• Required Probability = (No.of favorable outcomes) / (Total no of possible outcomes) = 32/36 = 8/9

Hence,

• 8/9 = p/q => p = 8 , q = 9 .
• √(2pq) = √(2 * 8 * 9) = √(144) = 12 (Ans.)

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