Question

Radhika's age was half as Suhas age if the ratio of the present ages is 3 is to 4 what will be the sum of their present ages

Answer 1

HEY MATE

$\huge\mathfrak\red{Solution}$

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10 years later

Let the Radhika's age be x

suhas age will be 2x

Their present age will be

Radhika's - x+10

suhas - 2x+10

age ratio =

(x+10)/(2x+10)=3/4

by cross multiplication

4x+40=6x+30

6x-4x=40-30

2x=10

x=5

Radhika's present age

=5+10=15

Suhas's present age=2*5+10 =20

Sum of their ages=15+20 =35

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Answer 2

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