Question

Radiation of wavelength, 280 nm passed through 1.0 mm of a solution that
contained
an aqueous solution of the amino acid tryptophan at a
concentration of 0.50 mmol L-. The light intensity is reduced to 54% of its
initial value. Calculate the absorbance and the molar absorption coefficient
of tryptophan at 280 nm.
What would be the transmittance through a cell of thickness 2.0 mm?​

Answer 1

Answer:

Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire. In wireless systems, this length is usually specified in meters (m), centimeters (cm) or millimeters (mm).

Answer 2

Given :

l = 1mm = 1×10⁻¹cm

c = 0.5mmolL⁻¹ = 0.5×10⁻³mol dm⁻³

To find :

a) Absorbance and the molar absorption coefficient  of tryptophan at 280 nm.

b) The transmittance through a cell of thickness 2.0 mm

Solution :

a) A = log (I / I₀)

A = log (100 / 54)

A = 0.2676

A = εcl

0.2676 = ε × 0.5 × 10⁻³ × 1 × 10⁻¹

ε = 5352 dm³ mol⁻¹ cm⁻¹

b) l =  2mm = 2 × 10⁻¹cm

log (1 / T) = εcl

log (1 / T) = 5352 × 0.5 × 10⁻³ × 2 × 10⁻¹

T = 0.2916