Radiation of wavelength lambda is incident on a photocell.the fastest emitted electron has a speed v.if the wavelength is vhanged to 3lambda/4,the sleed of the fastest emitted electron will be A)>v(4/3)^1/2
B)
Answers
Answered by
0
Answer:
you ask very good question you ask very good question you ask very good question you ask very good question you ask very good question you ask very good question you ask very good question you ask very good question you ask very good question you ask very good question you ask very good question you ask very good question you ask very good question you ask very good question the same thing
Answered by
0
Answer:
Radiation of wavelength λ is incident on a photocell. The fastest emitted electron has a speed v. If the wavelength is changed to 43λ, the speed of the fastest emitted electron will be : A .
Similar questions