Radiation power of 3.31 Watt is falling on a surface. If 20% of light is absorbed
and remaining is reflected back, calculate number of photons reflected per second.
Take the frequency of each photon 1012 Hz. and h=6.62x10-34 J-s
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Answer:
Power of the source = 62 watt
Energy emitted in a second = 62 joules
So, number of photons emitted in a second =
hC
62λ
=
6.626×10
−34
×3×10
8
62×4800×10
−10
photons / sec
=1.4962×10
20
photons / sec
≈1.5×10
20
photons /sec
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