Radiations of two photon energies twice and five times the work function of metal are incident successively on the metal surface. The ratio of the maximum velocity of the photoelectrons emitted in the two cases will be
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Answer:
1:2.
Explanation:
Since, we know the equation of energy as E - Wo = 1/2mv^2. Where Wo is the work function of the given metal element.
So, for the first case the equation will be; 2Wo - Wo = 1/2m(v1)^2. For the second equation we have 5Wo - Wo = 1/2m(v2)^2.
Hence, from the two equations we will have Wo/4Wo = (v1/v2)^2. Hence, the ratio of the velocities will be 1:2.
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