Question

Radical centre of the circles drawn on the sides as a diameter of triangle formed by the lines
3x - 4y + 6 = 0, X-y +2 = 0 and 4x + 3y - 17 = 0 is :
(A) (3,2)
(B) (3,-2)
(C) (2, -3)
(D) (2,3)
​

Answer 1

Answer:

I think option B is the correct answer