Question

Radical centre of the circles drawn on the
sides as diameter of triangle formed by
the lines 3x - 4y + 6 = 0,
x – y + 2 = 0 and
4x + 3y – 17 = 0​

Answer 1

(2,3) would be the Radical center of the circles drawn on the  sides as the diameter of the triangle formed by  the lines 3x - 4y + 6 = 0,  x – y + 2 = 0 and  4x + 3y – 17 = 0​.

Step-by-step explanation:

As we know,

$R_{1}$ ⊥ $C_{1} C_{2}$

$R_{2}$ ⊥ $C_{2}C_{3}$

$R_{3}$ ⊥ $C_{2}C_{3}$

The radical center is characterized as the orthocenter of triangle

3x - 4y + 6 = 0,            3x - 4y + 6 = 0

x – y + 2 = 0

4x + 3y – 17 = 0​,        4x + 3y – 17 = 0

∵ (2, 3) is the correct answer.

Learn more: Radical Circle

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