Question

radioactive material A has decay constant 8 lambda and material B has decay constant 1 lambda.initially they have some no of nuclei.after what time the ratio of no of nuclei of material B to that A will be 1/e? ​

Answer 1

Answer: Here is your answer.

Explanation:

Answer 2

Answer:

$t=\frac{1}{7(lambda)}$

Explanation:

The number of nuclei of a radioactive material at time 't' is given by:

N = N₀$e^{-(lambda)t}$   where N₀ is initial number of nuclei

Since both A and B have same number of initial nuclei,

The ratio is given by,

$\frac{1}{e} =\frac{No(e^{-(lambda)t} )}{No(e^{-8(lambda)t}}$

On solving the expression;

$e^{-1}=e^{7(lambda)t}\\ \\t=\frac{1}{7(lambda)}$

Hope this answer helped you :)