Question

Radiondize the denominator in
1/√7+√6​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$\frac{1}{\sqrt{7} +\sqrt{6} }$

$= \frac{1}{\sqrt{7} +\sqrt{6} } \cdot \frac{\sqrt{7}-\sqrt{6} }{\sqrt{7}-\sqrt{6} }$

$= \frac{\sqrt{7} -\sqrt{6} }{\sqrt{7} ^{2} -\sqrt{6} ^{2} }$

= $\frac{\sqrt{7} -\sqrt{6} }{7-6}$

= ${\sqrt{7} -\sqrt{6} }$

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