Chemistry, asked by samdade, 1 year ago

radition of lamda=155 nm was irradiated on li (work function =5ev) pate the stopping potential (in ev) is

Answers

Answered by tanishqsingh

4

Energy = 12400/1550 eV
E=8eV
E=work function +revs
8=5+Vs
Vs=3V

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