Radiue of a circle is 10cm . the length of a chord of a chord of a circle is 16 cm. find the distance of the chord form centre .
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Answer:
Step-by-step explanation:
From the figure shown,
Radius=OA=10cm.
AB is the chord drawn with the length=16 cm.
We know,
perpendicular drawn from the centre of the circle to the chord ,bisects the chord
hence, C is the midpoint of AB.
Therefore,
AC= AB = 16 = 8
2 2
So using Pythagoras Theorem:
OA² = OC² + AC²
10² = OC² + 8²
100=OC² + 64
OC² =36
OC=6cm
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