Question

radius at the Earth is 6.4 x 10 km, height at the Mount Everest is 8848 km. If the value of acceleration due to gravity as
of the Earth is 9.8 m/s calculate the value of acceleration due to gravity at the top. Also find the weight of the body of
on the top of the Mount Everest.
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Variation in Value of Acceleration due to Gravity

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Asked on December 26, 2019 by

Rupan Balla

What is the acceleration due to gravity on the top of Mount Everest ? Mount Everest is the highest mountain peak of the world at the height of 8848 m. The value at sea level is 9.80 ms

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ANSWER

Given,

h=8848m

The value of sea level is 9.08m/s

2

So,

Let g

′

be the acceleration due to the gravity on the Mount Everest.

g

′

=g(1−

h

2h

)

=9.8(1−

6400000

17696

)

=9.8(1−0.00276)

9.8×0.99724

=9.773m/s

2

Thus, the acceleration due to gravity on the top of Mount Everest is =9.773m/s

2