Question

Radius difference between 4th and 6th bohr orbit of H atom (1) 10.58 A (2) 1.058 A
(3) 5.29 A
(4) 52.9 A

Answer 1

Answer:

10.58

Explanation:

r1=0.529×n^2/z=0.529×4^2=0.529×16=0.8464

r2=0.529×n^2/z=0.529×6^2=0.529×36=1.9044

therefore,

r2-r1=1.9044-0.8464

=10.58A

Answer 2

The radius difference between the 4th and 6th Bohr orbit of the Hydrogen(H) atom is 10.58 Å

Given:

Hydrogen(H) atom

To Find:

The radius difference between the 4th and 6th Bohr orbit of the Hydrogen(H) atom.

Solution:

We are required to find the radius difference between the 4th and 6th Bohr orbit of the Hydrogen(H) atom.

The radius of the Bohr model is given as

rₙ = (0.529Åxn²)/Z  -------(1)

where Z is the atomic number of the atom

n is the Bohr orbit number

For Z = 1(Hydrogen), n = 4th orbit in equation(1)

r₁ = (0.529×n²)/Z Å

= 0.529×4² Å

= 0.529×16 Å

= 8.464 Å

For Z = 1(Hydrogen), n = 6th orbit in equation(1)

r₂ = 0.529×n²/Z Å

= 0.529×6² Å

= 0.529×36 Å

= 19.044 Å

Radius difference between 4th and 6th Bohr orbit of H atom = r₂-r₁

= 19.044-8.464 Å

= 10.58 Å

Therefore, The radius difference between the 4th and 6th Bohr orbit of the Hydrogen(H) atom is 10.58 Å

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