Radius difference between 4th and 6th bohr orbit of H atom (1) 10.58 A (2) 1.058 A
(3) 5.29 A
(4) 52.9 A
Answers
Answer:
10.58
Explanation:
r1=0.529×n^2/z=0.529×4^2=0.529×16=0.8464
r2=0.529×n^2/z=0.529×6^2=0.529×36=1.9044
therefore,
r2-r1=1.9044-0.8464
=10.58A
The radius difference between the 4th and 6th Bohr orbit of the Hydrogen(H) atom is 10.58 Å
Given:
Hydrogen(H) atom
To Find:
The radius difference between the 4th and 6th Bohr orbit of the Hydrogen(H) atom.
Solution:
We are required to find the radius difference between the 4th and 6th Bohr orbit of the Hydrogen(H) atom.
The radius of the Bohr model is given as
rₙ = (0.529Åxn²)/Z -------(1)
where Z is the atomic number of the atom
n is the Bohr orbit number
For Z = 1(Hydrogen), n = 4th orbit in equation(1)
r₁ = (0.529×n²)/Z Å
= 0.529×4² Å
= 0.529×16 Å
= 8.464 Å
For Z = 1(Hydrogen), n = 6th orbit in equation(1)
r₂ = 0.529×n²/Z Å
= 0.529×6² Å
= 0.529×36 Å
= 19.044 Å
Radius difference between 4th and 6th Bohr orbit of H atom = r₂-r₁
= 19.044-8.464 Å
= 10.58 Å
Therefore, The radius difference between the 4th and 6th Bohr orbit of the Hydrogen(H) atom is 10.58 Å
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