Radius OB AC
If AG=24 c, wha is AC?
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Let < A , < B and <C are internal angles of triangle ABC.
In given problem, we have given
AB = 10 , <A = 26∘ ,<B= 74∘
We know that sum of internal angles =180∘
< A + < B + <C = 180∘
<C = 180 - <A - <B
<C = 180 - 26∘ - 74∘
<C = 80 ∘
When for a triangle, we have given two internal angles and one side then for finding other sides we may apply Sine Law i.e;
AC/sin(74∘)=AB/sin(80∘)
AC= sin(74∘) (10/sin(80∘))
AC = 0.9851 (10/0.9939)
AC = 0.9851(10.06137)
AC = 9.9120
Hence it proved AC < 10
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