Question

radius of 1 arm of hydraulic lift is 4 times of radius of other arm .
what force should be applied on narrow arm to lift 100 kg?

Answer 1

Area of narrow arm=3.14
Area of another arm=3.14×16
F2=100
F1÷f2=3.14÷3.14×16
F1÷100=1/16
F1=100/16
=25/4=6.25kgf