Question

radius of a circle 10 cm there are two chords of length 16 cm each what will be the distance of these chords from the centre of the circle?

Answer 1

the answer is 6 cm
we know if you draw a straight line from the centre of the circle to the chord perpendicularly then the strickland intersect the cord Tu it's me. So from the pithagorus's theorem I got the the answer

Answer 2

Answer:

Given :

Radius of Circle = 10cm

Length of Chord = 16cm

To Find :

Find the distance of these chords from the centre of the circle ?

Solution :

OR = OP = 10cm [Radius]

PQ = RS = 16cm [Chord]

Perpendicular drawn from the centre of the circle to the chord bisects the chord,

➣ PU = ½ × PQ

➣ PU = ½ × 16

➣ PU = 8cm

Applying Pythagoras Theorem in ∆OUP :

➣ (OP)² = (OU)² + (PU)²

➣ (10)² = (OU)² + (8)²

➣ 100 = (OU)² + 64

➣ 100 - 64 = (OU)²

➣ 36 = (OU)²

➣ √36 = OU

➣ 6cm = OU

Therefore,

Congruent chords of the circle are equidistant from the circle are :

➣ OU = OT = 6cm

Hence,

The distance of the chord from the centre is 6cm.