Question

Radius of a circle is 10 cm and chord of a circle is 12 cm in length find the distance of the code from the centre of a circle

Answer 1

its ur ans.
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Answer 2

$\huge\boxed {\texttt {\fcolorbox {red} {aqua} {SOLUTION ;}}}$

Given, radius, r ,OB = OA = 10 cm

Length of chord = 12 cm

We know that the perpendicular drawn from the centre of a circle to a chord bisects the chord.

Let the circle have a centre named O. Let AB be the chord and The perpendicular bisects AB at C.

Hence, AC = CB = 1/2 × 12 CM = 6cm

Now Applying Pythagoras Theorem to triangle OBC,

OB^2 = OC^2 + CB^2
=> 100 = OC^2 + 36
=> OC = 8 cm

Hence, the distance of the chord from the centre is 8 cm.

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