radius of a circle is 10cm and the distance of a chord from the centre is 6cm .Hence the length of the chord is _____.
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Answer:ON= √84 cm
Step-by-step explanation:
Thus, In △OAP, Using Pythagoras theorem
OA
2
=AP
2
+OP
2
10
2
=AP
2
+6
2
AP
2
=64
AP=8 cm
Thus, AB=2AP=16 cm
Now, new chord CD is drawn with length 8 cm. Draw a perpendicular on CD from O to cut CD at N.
Now, In △ONC
OC
2
=NC
2
+ON
2
10
2
=4
2
+ON
2
ON=
84
cm
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