Question

Radius of a circle is 10cm and the length of one of its chords is 12cm.Find the distance of the chord from the centre.​

Answer 1

Step-by-step explanation:

perpendicular from centre to chord bisect the chord

so perpendicular OM will bisect chord AB

so AM =MB=1/2AB=6

OA =10(radius of circle)

in right triangle AOM

AO^2=OM^2+AM^2

or OM=√(AB^2-AM^2

=√100-36

=√64

=8

so distance bof chord from centre is 8 cm