radius of a circle is 10cm . the length of chord of a circle is 16 cm . find the distance of the chord from center
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Answer:
Given that,
AC = 12 cm [length of the given chord]
==> AB = 6 cm [total length of chord/2]
AO = 10 cm [Radius of the given circle]
From Pythagoras theorem,
H² = P² + B²
[ where H Is hypotenuse, P is perpendicular, B is base]
AO² = OB² + AB²
10² = OB² + 6²
OB² = 100 - 36
OB² = 64
==> OB = 8
Thus, the distance of the chord from the center of the circle is 8 cm.
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