radius of a circle is 25 cm and the distance of its chord from the centre is 4 cm what is the length of the chord?
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Answer:
As perpendicular from centre bisects the chord,
⇒CA=AD=20cm
In ΔOAD, OD
2
=OA
2
+AD
2
(Pythagoras thereom)
⇒OA
2
=OD
2
−AD
2
=25
2
−20
2
=625−400=225
⇒OA=15cm
OA is distance of chord from O.
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all will be fyn kk
which class ru dr
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