Question

Radius of a circle is 26 cm. Find the length of the chord if its distance from the centre is 10 cm .step by step​

Answer 1

Step-by-step explanation:

the explanation is given in the above image

r = 26cm

perpendicular distance to the cord = 10cm

by Pythagoras theorem,

let the chord length be 2x

so,

${x}^{2} + {10}^{2} = {26}^{2}$

${x}^{2} + 100 = 676$

${x}^{2} = 676 - 100$

${x }^{2} = 576$

x = 24cm..

the chord length = 2x = 48cm

hope this helps...

Answer 2

Answer:

= 48

Step-by-step explanation:

Step-by-step explanation:

perpendicular distance to the cord = 10cm

by Pythagoras theorem,

let the chord length be 2x

so,

{x}^{2} + {10}^{2} = {26}^{2}x

2

+10

2

=26

2

{x}^{2} + 100 = 676x

2

+100=676

{x}^{2} = 676 - 100x

2

=676−100

{x }^{2} = 576x

2

=576

x = 24cm..

the chord length = 2x = 48cm

hope this helps...