Question

radius of a circle is 3.5 and the angle subtended by a chord at the centre is the 90 degree find the area of the minor segment of the circle formed by these chord​

Answer 1

πr^2theta/360-1/2r^2sintheta

3.14*3.5^2*90/360-1/2*3.5^2*sin90

3.14*12.25/4-1/2*12.25*1

9.61-6.12

3.49

approx 3.5. answer

I hope my answer is correct.

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