Math, asked by seemapansare507, 4 months ago

Radius of a circle is 34cm and the distance of the chord

from the centre is 30m, find the length of the chord.​

Answers

Answered by IINiRII
1

Step-by-step explanation:

let the chord be AB

O be the center of the circle.

OC be the perpendicular from the centre of the circle to the chord AB.

[The perpendicular drawn from the centre of the circle to the chord bisect the circle.]

so, OC perpendicular AB

 {oc}^{2}  +  {ab}^{2}  =  {oa}^{2}  \\  {30}^{2}  +  {ac}^{2}  =  {34}^{2}  \\ 900 +  {ac}^{2}  = 1156 \\  {ac}^{2}  = 1156 - 900 \\  {ac}^{2}  = 256 \\ ac =  \sqrt{256}  \\ ac = 16 \\  \\ therefore \: ab = 2 \times 16 = 32 \\  \\  \\ hope \: it \: helps \: you \\ thank \: you

Answered by divyanjalichauhancar
1

LoL It's so easy. I hope this help you.

Thank you

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