radius of a circle is 4 cm and the length of chord of circle is 6 cm then the distance of the chord from the center is
Answers
Answered by
2
Step-by-step explanation:
ANSWER
Give OC =4 cm, Chord AB =6 cm
∵OC⊥AB⇒bisectsAB
⇒AC=CB=3cm
∴InOCA,OA
2
+AC
2
(PythagorasTheorem)
=4
2
+3
2
=16+9=25
⇒OA=5cm
Let EF be the chord at a distance of 3cm from the centre.
GIven, radius=OE =5 cm
∴In△OGE,EG
2
=OE
2
−OG
2
=5
2
−3
2
=25−9=16
⇒EG=4cm
∴EF=2×EG=8cm
(Line from centre ⊥ to chord bisects the chord )
Similar questions
Math,
3 months ago
Science,
3 months ago
Math,
3 months ago
CBSE BOARD X,
7 months ago
Math,
11 months ago