Radius of a circle is 5 cm. The length of a chord of the circle is 8 cm. Find the distance of
the chord from the centre.
Answers
Answered by
2
Answer:
⇒ In figure, PQ is a chord, OP is radius of a circle and OM is distance of chord from center.
⇒ OP=5cm [ Given ]
⇒ PQ=8cm [ Given ]
⇒ OM⊥PQ
⇒ PM=MQ=
2
PQ
=
2
8
=4cm
⇒ OP
2
=OM
2
+PM
2
[ By using Pythagoras theorem ]
⇒ 5
2
=OM
2
+4
2
∴ OM
2
=5
2
−4
2
∴ OM
2
=25−16
∴ OM
2
=9
∴ OM=3cm
Answered by
1
Answer:
3
Step-by-step explanation:
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