Question

Radius of a circle is 7 cm and angle of sector is 90’. Find the area
of minor section of circle,​

Answer 1

Answer:

area of minor sector = theta/360 ×πr square

90/360 ×22/7 ×7×7

Now, 11×7/2 = 77/2

=38.5cm square. Ans.....

hope it helps uu

Answer 2

Here is your answer mate:

Radius of the circle: 7cm

angle of sector = 90 degree

since the angle is 90 degree it forms a quadrant

Area of minor sector (one quadrant)

= Ф/360 + πr^2

= 90/360 x 22/7 x 7 x 7

= 1/4 x 22 x 7

= 1/4 x 154

= 36

thus the area of the minor sector is 36 cm^2

hope this helps you buddy

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