Math, asked by saikrishna16, 1 year ago

radius of a circle whose centre is (3,2) and passes through (-5,6)

Answers

Answered by kir2
8
 \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} }
 \sqrt{( - 5 - 3) {}^{2} + (6 - 2) {}^{2} }
 \sqrt{64 + 16 }
 4 \sqrt{5}
8.94

HOPE IT HELPS!!!
Similar questions
Math, 1 year ago