Question

RADIUS OF A CIRCLE WITH CENTRE O IS 25 CM FIND THE DISTANCE OF A CHORD FROM THE CENTRE IF LENGTH OF THE CHORD IS48 CM​

Answer 1

Answer:

Step-by-step explanation:

Given ' O ' is the centre of the circle.

Radius ( OA ) = 25 cm

Distance center to Chord = OM

Chord ( AB ) = 48 cm

OM perpendicular to AB.

and

OM bisects AB.

AM = AB/2 = 48/2 = 24 cm

In ∆OAM ,

<AMO = 90°

By Phythogarian theorem ,

OM² + AM² = OA²

OM² + 24² = 25²

OM² = 25² - 24²

OM² = ( 25 + 24 )( 25 - 24

OM² = 49

OM = 7cm

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Answer 2

Answer: 2 cm

Step-by-step explanation:

If radius is 25 cm then the dia

eter is 50 cm

D=50cm

The chord is 48 cm

So the distance between the two is

50-48=2 cm