Question

Radius of a circle with centre 'o' is 25cm . Find the distance of a chord from centre if the length of the chord is 48cm

Answer 1

Answer:

answer is 7cm

Step-by-step explanation:

using Pythagoras theorem..

625-576=47

Answer 2

Step-by-step explanation:

AnswEr:-

Required Distance is 7cm.

Step by Step Explanation:-

Given:-

A Circle with Center 'O'.

Radius of Circle = 25 cm.

Length of the Circle= 48cm.

To find :-

Distance of Chord

Finding:-

$:\implies\sf\; AB = \dfrac{BC}{2}$

$:\implies\sf\; AB = \dfrac{48}{2}$

$:\implies\sf\; AB = 24 cm$

$:\implies\sf\; OB = 25 cm$

$\rule{150}2$

Now, In ∆ OAB

By Using Pythagoras theorem:-

$:\implies\sf\; OB^2 = OA^2 + AB^2$

$:\implies\sf\; 25^2 = OA^2 + 24^2$

$:\implies\sf\; OA^2 = (25 + 4) (24 - 4)$

$:\implies\sf\; OA^2 = 49$

$:\implies\sf\; OA = \sqrt{49}$

$:\implies\large\boxed{\sf{\red{OA = 7cm}}}$

This is the required Distance.

$\rule{150}2$