Question

radius of a circle with centre o is25 cm. find the distance of a chord from centre if length of chord is 48 cm​

Answer 1

Applying Pythagoras theoram

Length of chord assuming Hypotenuse=48/2=24

Center assuming base

Distance of chord=Perpendicular

Let the side of Hypotenuse be AC and others are BC and AB

(AC)²= (AB)²+(BC)²

(25)² = (AB)² + (24)²

625-576 = (AB)²

49= (AB)²

7cm=(AB)

Answer 2

length of chord is 7 CM

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