Question

Radius of a circle with centre of is 41units . length of a chord PQ is 80units , find the distance of the chord from the centre of the circle​

Answer 1

Given :

• Radius of Circle = 41units
• Length of Chord = 80units

To Find :

• The distance of the chord from the centre of the circle.

Solution :

✰ Let PQ be the chord and let OM be the perpendicular drawn from the centre of the circle to the chord PQ. We know that, perpendicular drawn from the centre of the circle to the chord bisects the chord. So PM = MQ = 40units.

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✰ Now we will apply Pythagoras Theorem in the ∆PMO

Using Pythagoras theorem :

⟼ (PO)² = (OM)² + (PM)²

⟼ (41)² = (OM)² + (40)²

⟼ 1681 = (OM)² + 1600

⟼ 1681 - 1600 = (OM)²

⟼ 81 = (OM)²

⟼ √81 = OM

⟼ 9 units = OM

Thus Distance of the chord from the centre of the circle is 9 units

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Answer 2

Answer:

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